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QUINE-McCLUSKEY MINIMIZATION
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Quine-McCluskey minimization method uses the same theorem to produce the solution as the K-map method, namely X(Y+Y')=X |
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Minimization Technique
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- The expression is represented in the canonical SOP form if not already in that form.
- The function is converted into numeric notation.
- The numbers are converted into binary form.
- The minterms are arranged in a column divided into groups.
- Begin with the minimization procedure.
- Each minterm of one group is compared with each minterm in the group immediately below.
- Each time a number is found in one group which is the same as a number in the group below except for one digit, the numbers pair is ticked and a new composite is created.
- This composite number has the same number of digits as the numbers in the pair except the digit different which is replaced by an "x".
- The above procedure is repeated on the second column to generate a third column.
- The next step is to identify the essential prime implicants, which can be done using a prime implicant chart.
- Where a prime implicant covers a minterm, the intersection of the corresponding row and column is marked with a cross.
- Those columns with only one cross identify the essential prime implicants. -> These prime implicants must be in the final answer.
- The single crosses on a column are circled and all the crosses on the same row are also circled, indicating that these crosses are covered by the prime implicants selected.
- Once one cross on a column is circled, all the crosses on that column can be circled since the minterm is now covered.
- If any non-essential prime implicant has all its crosses circled, the prime implicant is redundant and need not be considered further.
- Next, a selection must be made from the remaining nonessential prime implicants, by considering how the non-circled crosses can be covered best.
- One generally would take those prime implicants which cover the greatest number of crosses on their row.
- If all the crosses in one row also occur on another row which includes further crosses, then the latter is said to dominate the former and can be selected.
- The dominated prime implicant can then be deleted.
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Example
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Find the minimal sum of products for the Boolean expression, f=(1,2,3,7,8,9,10,11,14,15), using Quine-McCluskey method. |
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Firstly these minterms are represented in the binary form as shown in the table below. The above binary representations are grouped into a number of sections in terms of the number of 1's as shown in the table below. |
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Binary representation of minterms |
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Minterms
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U
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V
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W
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X
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1
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0
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0
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0
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1
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2
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0
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0
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1
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0
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3
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0
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0
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1
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1
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7
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0
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1
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1
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1
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8
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1
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0
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0
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0
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9
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1
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0
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0
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1
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10
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1
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0
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1
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0
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11
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1
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0
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1
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1
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14
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1
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1
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1
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0
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15
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1
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1
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1
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1
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Group of minterms for different number of 1's |
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No of 1's
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Minterms
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U
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V
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W
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X
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1
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1
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0
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0
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0
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1
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1
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2
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0
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0
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1
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0
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1
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8
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1
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0
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0
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0
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2
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3
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0
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0
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1
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1
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2
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9
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1
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0
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0
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1
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2
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10
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1
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0
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1
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0
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3
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7
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0
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1
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1
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1
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3
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11
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1
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0
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1
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1
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3
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14
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1
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1
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1
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0
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4
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15
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1
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1
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1
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1
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Any two numbers in these groups which differ from each other by only one variable can be chosen and combined, to get 2-cell combination, as shown in the table below. |
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2-Cell combinations |
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Combinations
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U
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V
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W
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X
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(1,3)
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0
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0
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-
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1
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(1,9)
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-
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0
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0
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1
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(2,3)
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0
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0
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1
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-
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(2,10)
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-
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0
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1
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0
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(8,9)
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1
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0
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0
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-
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(8,10)
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1
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0
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-
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0
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(3,7)
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0
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-
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1
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1
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(3,11)
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-
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0
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1
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1
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(9,11)
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1
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0
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-
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1
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(10,11)
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1
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0
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1
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-
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(10,14)
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1
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-
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1
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0
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(7,15)
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-
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1
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1
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1
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(11,15)
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1
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-
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1
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1
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(14,15)
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1
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1
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1
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-
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From the 2-cell combinations, one variable and dash in the same position can be combined to form 4-cell combinations as shown in the figure below. |
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4-Cell combinations |
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Combinations
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U
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V
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W
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X
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(1,3,9,11)
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-
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0
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-
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1
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(2,3,10,11)
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-
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0
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1
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-
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(8,9,10,11)
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1
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0
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-
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-
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(3,7,11,15)
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-
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-
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1
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1
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(10,11,14,15)
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1
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-
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1
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-
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The cells (1,3) and (9,11) form the same 4-cell combination as the cells (1,9) and (3,11). The order in which the cells are placed in a combination does not have any effect. Thus the (1,3,9,11) combination could be written as (1,9,3,11). |
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From above 4-cell combination table, the prime implicants table can be plotted as shown in table below. |
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Prime Implicants Table |
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Prime Implicants
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1
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2
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3
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7
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8
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9
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10
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11
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14
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15
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(1,3,9,11)
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X
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-
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X
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-
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-
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X
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-
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X
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-
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-
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(2,3,10,11)
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-
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X
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X
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-
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-
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-
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X
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X
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-
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-
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(8,9,10,11)
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-
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-
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-
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-
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X
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X
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X
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X
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-
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-
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(3,7,11,15)
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-
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-
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-
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-
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-
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-
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X
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X
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X
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X
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-
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X
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X
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-
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X
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X
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-
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-
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-
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X
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-
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The columns having only one cross mark correspond to essential prime implicants. A yellow cross is used against every essential prime implicant. The prime implicants sum gives the function in its minimal SOP form. |
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Y = V'X + V'W + UV' + WX + UW |
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